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翻訳と辞書　辞書検索 [ 開発暫定版 ] スポンサード リンク Josephson energy ： ウィキペディア英語版 Josephson energy In superconductivity, the Josephson energy is the potential energy accumulated in the Josephson junction when a supercurrent flows through it. One can think of a Josephson junction as a non-linear inductance which accumulates (magnetic field) energy when a current passes through it. In contrast to real inductance, no magnetic field is created by a supercurrent in Josephson junction—the accumulated energy is a Josephson energy. == Derivation == For the simplest case the current-phase relation (CPR) is given by (aka the first Josephson relation): :$I\_s\; =\; I\_c\; \backslash sin(\backslash phi),$ where $I\_s\backslash ,$ is the supercurrent flowing through the junction, $I\_c\backslash ,$ is the critical current, and $\backslash phi\backslash ,$ is the Josephson phase, see Josephson junction for details. Imagine that initially at time $t=0$ the junction was in the ground state $\backslash phi=0$ and finally at time $t$ the junction has the phase $\backslash phi$. The work done on the junction (so the junction energy is increased by) :$$ U = \int_0^t I_s V\,dt = \frac \int_0^t I_s \frac\,dt = \frac \int_0^\phi I_c\sin(\phi) \,d\phi = \frac (1-\cos\phi). Here $E\_J\; =\; /$ sets the characteristic scale of the Josephson energy, and $(1-\backslash cos\backslash phi)$ sets its dependence on the phase $\backslash phi$. The energy $U(\backslash phi)$ accumulated inside the junction depends only on the current state of the junction, but not on history or velocities, i.e. it is a potential energy. Note, that $U(\backslash phi)$ has a minimum equal to zero for the ground state $\backslash phi=2\backslash pi\; n$, $n$ is any integer. 抄文引用元・出典: フリー百科事典『 ウィキペディア（Wikipedia）』 ■ウィキペディアで「Josephson energy」の詳細全文を読む スポンサード リンク 翻訳と辞書 : 翻訳のためのインターネットリソース Copyright(C) kotoba.ne.jp 1997-2016. All Rights Reserved.